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0=5x^2+16x-16
We move all terms to the left:
0-(5x^2+16x-16)=0
We add all the numbers together, and all the variables
-(5x^2+16x-16)=0
We get rid of parentheses
-5x^2-16x+16=0
a = -5; b = -16; c = +16;
Δ = b2-4ac
Δ = -162-4·(-5)·16
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*-5}=\frac{-8}{-10} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*-5}=\frac{40}{-10} =-4 $
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